As the defect is myopia so we need a diverging lens and the power of lens can be calculated as follows:
v=-80cm,u=-infinity (bcoz the person can see to the specific distance which is as at infinfinty for him)
we know that:1/f=1/v-1/u
so substituting the values:
1/f=-1/80-(-1/infinity)
1/f=-1/80+0(1/infinity=0)
1/f=-1/80
therefore,f=-80cm or -0.8m
now ,P=1/f
P=-1/0.8
P=-1.25D