Question 117 (i)

Science Application
The king cobra can reach a length of 558 cm. This is only about 60% of the length of the largest reticulated python. Find the length of the largest reticulated python.

Open in App

Solution

Length of the king cobra = 558 cm
According to the question.
60 % of length of reticulated python = 558 cm
$\Rightarrow \frac{60}{100} \times$ Length of reticulated python = 558 cm
$∴$ Length of reticulated python $= 558 \times \frac{100}{60} = 930 c m$

Suggest Corrections

Similar questions

Question 117 (iii)

Life Science Application
A DNA model was built using the scale 2 cm : 0.0000001 mm. If the model of the DNA chain is 17 cm long, what is the length of the actual chain?

Which one of the following is not a poisonous snake?

(a) Cobra

(b) Viper

(d) Krait

Q. The length and the breadth of a rectangular paper are

35 c m

and

22 c m

. Find the area of the largest circle which can be cut out of this paper.

Reticulate venation is found in dicot leaves while in monocot leaves venation is of parallel type. Biology being a 'Science of exceptions', find out any exception to this generalisation.

Q. Question 11
Is the area of the largest circle that can be drawn inside a rectangle of length a cm and breadth b cm

(a > b) i s π b^{2} c m

? why?

Join BYJU'S Learning Program

Explore more

Bar Graph

Standard VII Mathematics

Join BYJU'S Learning Program

Question 117 (i) Science Application The king cobra can reach a length of 558 cm. This is only about 60% of the length of the largest reticulated python. Find the length of the largest reticulated python.

Length of the king cobra = 558 cm According to the question. 60 % of length of reticulated python = 558 cm ⇒60100× Length of reticulated python = 558 cm ∴ Length of reticulated python =558×10060=930 cm

Question 117 (i)

Science Application
The king cobra can reach a length of 558 cm. This is only about 60% of the length of the largest reticulated python. Find the length of the largest reticulated python.

Length of the king cobra = 558 cm
According to the question.
60 % of length of reticulated python = 558 cm
$\Rightarrow \frac{60}{100} \times$ Length of reticulated python = 558 cm
$∴$ Length of reticulated python $= 558 \times \frac{100}{60} = 930 c m$