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Question

i. σa m. qa+qb4πR2
ii. σb n. qa4πa2
iii. σR o. qb4πb2
Match the table.

A
(i, o), (ii, n), (iii, m)
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B
(i, n), (ii, o), (iii, m)
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C
(i, m), (ii, o), (iii, n)
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D
(i, n), (ii, m), (iii, o)
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Solution

The correct option is C (i, n), (ii, o), (iii, m)

σA=qA4πa2σB=qb4πb2σR=qA+qB4πR2
where,a,b,R are
radii of surface A,B&R respectively
if surface A&B have ve charge, then surface are would have a positive charge.

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