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Power Law

Question 5 i ...

Question

Question 5(i)
Simplify:
(i) $\frac{(2^{5})^{2} \times 7^{3}}{8^{3} \times 7}$

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Solution

(i) $\frac{(2^{5})^{2} \times 7^{3}}{8^{3} \times 7} = \frac{2^{5 \times 2} \times 7^{3}}{(2^{3})^{3} \times 7}$
$= \frac{2^{10} \times 7^{3}}{2^{9} \times 7}$
$= 2^{10 - 9} \times 7^{3 - 1} = 2 \times 7^{2}$
$= 2 \times 49$
$= 98$

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