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Question

(i) sin-112-2sin-112
(ii) sin-1cossin-132

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Solution

(i)

sin-112-2sin-112=sin-112-sin-12×121-122=sin-112-sin-12×12=sin-112-sin-11=sin-1sinπ6-sin-1sinπ2=π6-π2=-π3
(ii)
sin-1cossin-132=sin-1cossin-1sinπ3=sin-1cosπ3=sin-112=sin-1sinπ6=π6

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