(i) Sum of n terms of a sequence, Sn = n2(n + 1)
To find the first three terms of the sequence, we need to find S1, S2 and S3.
For n = 1, we have:
S1 = 12(1 + 1) = 1 × 2 = 2
For n = 2, we have:
S2 = 22(2 + 1) = 4 × 3 = 12
For n = 3, we have:
S3 = 32(3 + 1) = 9 × 4 = 36
Thus, we get:
t1 = S1 = 2
t2 = S2 – S1 = 12 – 2 = 10
t3 = S3 – S2 = 36 – 12 = 24
Therefore, the first three terms of the sequence are 2, 10 and 24.