(i) Solve $12 x^{2} - 9 y + 12 - 16 x^{2}$
(ii) Find the sum of $9 m y + 10 m y^{2}$ and $- 9 x y - 20 m y^{2}$

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Solution

(i) $12 x^{2} - 9 y + 129 - 16 x^{2}$
$= 12 x^{2} - 16 x^{2} - 9 y + 129$
$= - 4 x^{2} - 9 y + 129$

(ii) $(9 m y + 10 m y^{2}) + (- 9 x y - 20 m y^{2})$
$= 9 m y + 10 m y^{2} - 9 x y - 20 m y^{2}$
$= 9 m y - 9 x y + 10 m y^{2} - 20 m y^{2}$
$= 9 m y - 9 x y - 10 m y^{2}$
$= 9 y (m - x) - 10 m y^{2}$

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(i) solve 12x² - 9y + 129 - 16x²

(ii)find the sum of 9my + 10my² and -9xy - 20my²

(iii) 56c - 10c² is subtracted from the sum of 10c² and (-96c² -23c). Find the desired result.

\frac{2}{x} + \frac{3}{y} = \frac{9}{x y} and \frac{4}{x} + \frac{9}{y} = \frac{21}{x y}

y^{2} (4 x^{2} - 108) = x (x^{3} - 9 y^{3}), 2 x^{2} + 9 x y + y^{2} = 108

{12 x}^{2} + 25 x + 12 = 0

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