Question

$i)Solve\frac{4}{3}+\frac{5}{6}ii)Solve\frac{-3}{7}+\left(\frac{-5}{21}\right)$.

Answer 1

$i)Weknowthat,\frac{4}{3}=\frac{4\times 2}{3\times 2}=\frac{8}{6}(\frac{8}{6}isequivalentrationalnumberof\frac{4}{3})$

$So,\frac{4}{3}+\frac{5}{6}=\frac{8}{6}+\frac{5}{6}=\frac{13}{6}$

$ii)Weknowthat\frac{-3}{7}=\frac{3\times 3}{7\times 3}=\frac{-9}{21}$

$So,\frac{-3}{7}+\left(\frac{-5}{21}\right)=\frac{-9}{21}+\frac{-5}{21}$

$=\frac{-9-5}{21}=\frac{-14}{21}$