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Unlike Fractions

Question 1i:s...

Question

Question 1(i) :

Solve:

$\frac{2}{3} + \frac{3}{4} + \frac{1}{2}$

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Solution

Fractions whose denominators are different are called unlike fractions.

$\frac{2}{3}$ , $\frac{3}{4}$ and $\frac{1}{2}$ are unlike fractions.

The LCM of the denominator of the given fractions i.e. L.C.M of 3, 4, 2 is 12.

$∴ \frac{2}{3} + \frac{3}{4} + \frac{1}{2} = \frac{2 \times 4 + 3 \times 3 + 1 \times 6}{12} = \frac{8 + 9 + 6}{12} = \frac{23}{12} = 1 \frac{11}{12}$

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Similar questions

Q. Question 124(ii)
Name the property used in each of the following:

\frac{- 2}{3} \times [\frac{3}{4} + \frac{- 1}{2}] = [\frac{- 2}{3} \times \frac{3}{4}] + [\frac{- 2}{3} \times \frac{- 1}{2}]

Question 98(i)

Simplify:
${(\frac{1}{4})}^{- 2} + {(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2}$

Question 4(b) :

Look at the figures and write ‘<’ or ‘>’ between the given pairs of fractions:

$\frac{3}{4} □ \frac{2}{6}$

Question 98(ii)

Simplify:
${({(\frac{- 2}{3})}^{- 2})}^{3} \times {(\frac{1}{3})}^{- 4} \times 3^{- 1} \times \frac{1}{6}$

Simplify:

$4 \frac{2}{3} + 3 \frac{1}{4}$

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Unlike Fractions

Standard VI Mathematics

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