Question

Question 9 (i)
Solve the following pair of equations
$x+y=3.3,\frac{0.6}{3x-2y}=-1\text{where}3x-2y\ne 0$.

Answer 1

Given pair of linear equations is
$x+y=\mathrm{3.3......}\left(i\right)$ and $\frac{0.6}{3x-2y}=-1$
The second equation can be expressed as follows:

$\frac{0.6}{3x-2y}=-1$

$\Rightarrow 0.6=-3x+2y\Rightarrow 3x-2y=-0.6.....\left(ii\right)$
Now, multiplying Eq. (i) by 2 and then adding with Eq. (ii), we get
$2x+2y=6.6$
$3x–2y=-0.6$
$\underset{–}{}$
$5x=6\Rightarrow x=\frac{6}{5}=1.2$

Now, put the value of $x$ in Eq. (i) to get the value of $y$.
$1.2+y=3.3$
$\Rightarrow y=3.3–1.2$
$\Rightarrow y=2.1$
Hence, the required values of $x$ and $y$ are 1.2 and 2.1, respectively.