Question

I spent $\frac{7}{10}$hour on one day and $\frac{11}{15}$hour on the second day to finish my homework. How much time did I spend to do my homework in two days?

Answer 1

Time taken to complete the homework on the first day $=\frac{7}{10}$hours

Time taken to complete the home work on the first day $=\frac{11}{15}$hours

Convert the above unlike fractions into like fractions by obtaining the L.C.M of their denominators, we get

L.C.M of $10$and $15$ $=$$30$

Time taken to complete the work on the first day $=$ $\frac{7}{10}=\frac{7\times 3}{10\times 3}=\frac{21}{30}$hours

Time taken to complete the work on the second day $=$ $\frac{11}{15}=\frac{11\times 2}{15\times 2}=\frac{22}{30}$hours

Total time taken to complete the work in two days $=$$\frac{21}{30}$$+$$\frac{22}{30}$

$=\frac{21+22}{30}$

$=\frac{43}{30}$hours

Thus, total time taken to complete the homework in two days $=\frac{43}{30}$hours. Answer