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Question

I: x+14<x+2 is true for x(2,).
II: The solution of the inequation 3x+2>(19)1/x is (0,).
Which of the above statement(s) is/are true?

A
only I
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B
only II
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C
both I and II
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D
neither I nor II
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Solution

The correct option is C both I and II
x+14<x+2x+14>0andx+2>0Asyy>0(1)Sowecandirectlysquaretheequation(x+2)2>(x+14)x2+4x+4x14>0x2+3x10>0(x+5)(x2)>0x(,5)(2,)Asx>2Sothesolutionsetisx(2,)PartII3x+2>(19)1x3x+2>(3)2x3x+2+2x>30x+2+2x>0x2+2x+2x>0Sothesolutionsetisx>0

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