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Question

(i)Subtract 4a7ab+3b+12 from 12a9ab+5b3.
(ii)Subtract 3xy+5yz7zx from 5xy2yz2zx+10xyz.
(iii)Subtract 4p2q3pq+5pq28p+7q10 from 183p11q+5pq2pq2+5p2q.

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Solution

1)(12a9ab+5b3)(4a7ab+3b+12)=8a2ab+2b15

2)(5xy2yz2zx+10xyz)(3xy+5yz7zx)=2xy7yz+5zx+10xyz

3)(183p11q+5pq2pq2+5p2q)(4p2q3pq+5pq28p+7q10)=28+5p18q+8pq7pq2+p2q

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