Question 94 i Taking x -4-9- y -5-12 and z -7-18-Find x-y-z

Given, x = 4/9, y = 5/12 and z = 7/18 Here, x +(y+z) = 4/9 + (5/12+7/18 ) = 4/9+ (5 × 3 +7 × 2/36 ) [∵ LCM of 12 and 18 = 36] = 4/9+ (15+14/36 ) = ...

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Standard VI

Mathematics

Formation of Algebraic Expressions

Question 94 i...

Question

Question 94 (i)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$

Find $x + (y + z)$ .

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Solution

Given, $x = \frac{- 4}{9}, y = \frac{5}{12} a n d z = \frac{7}{18}$
Here, $x + (y + z) = \frac{- 4}{9} + (\frac{5}{12} + \frac{7}{18}) = \frac{- 4}{9} + (\frac{5 \times 3 + 7 \times 2}{36})$ [ $∵$ LCM of 12 and 18 = 36]
$= \frac{- 4}{9} + (\frac{15 + 14}{36}) = \frac{- 4}{9} + \frac{29}{36} = \frac{- 4 \times 4 + 29}{36} = \frac{13}{36}$

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Question 94 (k)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$ find
$x - (y + z)$

Question 94 (h)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18}$

Find $(x - y) + z$ .

Question 94 (j)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18}$ .

Find $x \div (y \div z)$ .

Question 94 (g)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18}$

Find $(x \div y) \times z$ .

Question 94 (e)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$ find
The reciprocal of x + y.

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Formation of Algebraic Expressions

Standard VI Mathematics

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Question 94 (i) Taking x=−49,y=512 and z=718, Find x+(y+z).

Given, x=−49,y=512 and z=718 Here, x+(y+z)=−49+(512+718)=−49+(5×3+7×236) [∵ LCM of 12 and 18 = 36] =−49+(15+1436)=−49+2936=−4×4+2936=1336

Question 94 (i)

Taking $x = \frac{- 4}{9}, y = \frac{5}{12}$ and $z = \frac{7}{18},$

Find $x + (y + z)$ .