Question

I: The boiling point of $H_{2}O$ is higher than the boiling point of $H_{2}S$.
II: $H_{2}S$ has a greater molecular mass than $H_{2}O$.

Answer 1

(I) Boiling point of $H_{2}O$ is higher than $H_{2}S$ due to high electronegativity of $O$. It makes intermolecular $H$-bonding with $H$ of other water molecules. Hence, true.

(II) $H_{2}S$ has greater molecular mass than $H_{2}O$.

Molecular mass;

$H_{2}S=2+32=34$ g/mol

$H_{2}O=2+16=18$ g/mol

This is due to the more atomic number of $S$ than $O$.