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Question

I : The number of five digit numbers that can be formed with 0,1,2,3,5 which are divisible by 5 is 18.
II : The sum of all four digit numbers that can be formed with 1,2,3,4 so that no digit being repeated in any number is 66660.
Which of the above statements is true?

A
only I
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B
only II
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C
Both I and II
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D
Neither I nor II
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Solution

The correct option is D only II
Case I: last digit =0
CI=4!=24
Case II Last digit =5
CII=3×3!=18
S=CI+CII=42
II Sum here is
S=3!×[1+2+3+4]×[100+101+102+103]
=6×10×[1111]
=60×1111
S=66660

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