(i) The sum of the binomial coefficients of the expansion (x+1x)n is 2n. (ii) The term independent of x in the expansion of (x+1x)n is 0 when is even. Which of the above statements is correct?
A
Only (i)
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B
Only (ii)
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C
both (i) and (ii)
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D
neither (i) nor (ii)
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Solution
The correct option is A Only (i) Sum of all the coefficients in a binomial expansion of type (axp+bxq) for a>0b>0 is always 2n. Now if n is even there will be n+1 terms. Hence, there will odd number of terms. Hence, the middle term will be the term independent of in (x+1x)n. Hence, T(n/2+1) is the term independent of x. Hence only (i) is true.