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Byju's Answer
Standard IX
Mathematics
(x±a)(x±b) = x²±(a+b)x+ab.
Question 7iUs...
Question
Question 7(i)
Using
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
,
find
51
2
−
49
2
Open in App
Solution
51
2
−
49
2
=
(
51
+
49
)
(
51
−
49
)
[
U
s
i
n
g
i
d
e
n
t
i
t
y
(
a
−
b
)
(
a
+
b
)
=
a
2
−
b
2
]
=
100
×
2
=
200
Suggest Corrections
0
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(x±a)(x±b) = x²±(a+b)x+ab.
Standard IX Mathematics
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