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Question

Question 2 (i)
Verify that each of the following is an AP and then write its next three terms.
0,14,12,34,

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Solution

Here, a1=0, a2=14, a3=12 and a4=34
a2a1=14, a3a2=1214=14, a4a3=3412=14
a2a1=a3a2=a4a3
Since the difference between successive terms are same, it forms an AP. The next three terms are,
a5=a1+4d

=a+4(14)=1, a6=a1+5d=a+5(14)=54
a7=a+6d=0+64=32

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