Question

(i) What is observed when a solution of potassium iodide is added to a sulution of lead nitrate taken in a test tube ?
(ii) What type of reaction is this ?
(iii) Write a balanced chemical equation to represent the above reaction.

Answer 1

(i) A yellow precipitate of lead iodide will be formed.

(ii) This is a double displacement reaction.

(iii) $Pb{(NO{)}_3}_2\left(aq\right)+2KI\left(aq\right)$ $\to$ $Pb{I}_2\left(s\right)$ + $2KN{O}_3\left(aq\right)$