(i) What is the role of sulphur in the vulcanisation of rubber?
(ii) Identify the monomers in the given polymer.
(iii) Arrange the following polymers in the decreasing order of their intermolecular forces: Terylene, Polythene, Neoprene.

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Solution

(i) The role of sulphur in vulcanisation of rubber is, it reacts with these chains and forms disulphide (or similar) bonds. These new bonds join two of the hydrocarbon chains together. In this manner a mesh like network is formed which is stronger than the separate hydrocarbon chains in natural rubber. All of this comes about by the formation of the disuphide (or trisulphide or ...) bonds.
(ii) The monomer of the given compound is :
Hexamethyldiamine - $H_{2} N (C H_{2})_{6} N H_{2}$ and Adipic Acid - $C O O H (C H_{2})_{4} C O O H$
(iii) Decreasing order of their intermolecular forces:
Terylene> Polythene> Neoprene

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Arrange the following polymers in increasing order of their intermolecular forces.

(i) Nylon 6, 6, Buna-S, Polythene.

(ii) Nylon 6, Neoprene, Polyvinyl chloride.

6

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{[- N H - {(C H_{2})}_{6} - N H - C O - {(C H_{2})}_{4} - C O -]}_{n}

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