(i) What is the work done by the porter when he climbs up a height of 10 m $(g = 10 {m s}^{- 2})$ ?

5 k J^{2}

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50 k J

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100 k J^{2}

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5 k J

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Solution

The correct option is D $5 k J$
The work done by the potter is defined as the product of the force and the displacement.

Work done = force $\times$ displacement
= $m \times g \times 10$ ( Since force = mass $\times$ gravity)

= $50 \times 10 \times 10$
= $5 K J$

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Similar questions

g = 10 m s^{- 2}

A man of mass 50 kg climbs up a ladder of height 10 m. Calculate:

(i) the work done by the man, and

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(a) What is the work done by the boy against the force of gravity?

(b) What would have been the work done if he uses a lift in climbing the same vertical height?

50 k g

100 m

g = 9.8 m / s^{2}

60 k g

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10 m

(T a k e g = 10 m s^{- 2})

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