$(i)$ What per cent of $1 k g$ is $125 g$ ?
$(i i)$ What per cent of $80 m$ is $24 m$ ?

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Solution

$(i)$
We know that, $1 k g = 1000 g$
Let $x %$ of $1 k g$ be $125 g$ .
$\Rightarrow \frac{x}{100} \times 1000 g = 125 g$
$\Rightarrow x \times 10 = 125$
$\Rightarrow x = \frac{125}{10}$
$\Rightarrow x = 12.5$
i.e., $12.5 %$ of $1 k g$ is $125 g$

$(i i)$
Let $x %$ of $80 m$ be $24 m$ .
$\Rightarrow \frac{x}{100} \times 80 m = 24 m$
$\Rightarrow \frac{4 x}{5} = 24$
$\Rightarrow 4 x = 24 \times 5$
$\Rightarrow x = \frac{24 \times 5}{4}$
$\Rightarrow x = 6 \times 5$
$\Rightarrow x = 30$
i.e., $30 %$ of $80 m$ be $24 m$ .

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(i) What per cent of 1 kg is 125 g ?(ii) What per cent of 80 m is 24 m?

(i)We know that, 1 kg=1000 g Let x% of 1 kg be 125 g.⇒x100×1000 g=125 g⇒x×10=125⇒x=12510⇒x=12.5i.e., 12.5% of 1 kg is 125 g (ii)Let x% of 80 m be 24 m.⇒x100×80 m=24 m⇒4x5=24⇒4x=24×5⇒x=24×54⇒x=6×5⇒x=30i.e., 30% of 80 m be 24 m.

$(i)$ What per cent of $1 k g$ is $125 g$ ?
$(i i)$ What per cent of $80 m$ is $24 m$ ?