Question

(i) What will be in the unit place of a number if the square of a number ends in 6?
(ii) Which number must be added to 1886 to make it a perfect square?

Answer 1

(i) Unit place of a number will have either 4 or 6 in its units place.
(ii) Given number = 1886


From the above it is clear that, $43<\sqrt{1886}<44$
$\therefore (44{)}^2=1936$
$1936-1886=50$
Hence, 50 should be added to 1886 to make it a perfect square