Question

(i) Why $H_{3}P{O}_3$ diprotic in nature ? Draw the structure.
(ii) Why $H_2$S less acidic than $H_2$ Te ?
(iii) Give hybridization and draw the structure of $Xe{F}_6$.

Answer 1

i) These protons can be abstracted that's why it is diprotic.

ii) $H_{2}S$ is less acidic than $H_{2}Te$ becomes as we more down the group bond dissociation energy decreases. So, $H_{2}Te$ has higher capability to release $H^{+}$ compared to that of $H_{2}S$.

iii) ${sp}^3{d}^3$ hybridization. ${XeF}_6$ has distorted octahedral structure.