Question

Question 2 (i)
Write a Pythagorean triplet whose one member is:

6

Answer 1

There are three numbers $2m,m^2-1and{m}^2+1,$ in a Pythagorean Triplet$(for,m>1)$.

$Here,2m=6\Rightarrow m=\frac{6}{2}=3\therefore \text{Second number}(m^2-1)=(3{)}^2-1=9-1=8\text{And third number}(m^2+1)=(3{)}^2+1=9+1=10$

Hence, Pythagorean triplet is (6, 8, 10).