Question

Question 3 (i)
Write the first three terms of the AP’s, when a and d are as given below:
$a=\frac{1}{2},d=-\frac{1}{6}$

Answer 1

Given that,
First term (a) =$\frac{1}{2}$ and common difference (d) $=-\frac{1}{6}$
$\because$ nth term of an AP, $T_n=a+(n-1)d$
$\therefore$ Second term of the AP, $T_2=a+d=\frac{1}{2}-\frac{1}{6}=\frac{2}{6}=\frac{1}{3}$
Third term of the AP, $T_3=a+2d=\frac{1}{2}-\frac{2}{6}=\frac{1}{2}-\frac{1}{3}=\frac{3-2}{6}=\frac{1}{6}$