I- X-10241-2II- Y2-1024

The correct option is C x ≥ yx = 32 y = ± 32 x ≥ y ...

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Solving Linear Differential Equations of First Order

I. X=10241/2I...

Question

I. $X = (1024)^{\frac{1}{2}}$
II. $Y^{2} = 1024$

x > y

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x < y

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x \geq y

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x \leq y

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x = y

or relationship cannot be established

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Solution

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Factorise :
(i) $x^{3}$ −2 $x^{2}$ −x+2
(ii) 2 $y^{3}$ + $y^{2}$ −2y−1

x^{3} - 2 x^{2} - x + 2

x^{3} - 3 x^{2} - 9 x - 5

x^{3} + 13 x^{2} + 32 x + 20

2 y^{3} + y^{2} - 2 y - 1

\frac{(1 + i) x - i}{2 + i} + \frac{(1 + 2 i) y + i}{2 - i} = 1 \Rightarrow (x, y) =

(i) x^{3} - 2 x^{2} - x + 2

(i i) x^{3} - 3 x^{2} - 9 x - 5

(i i i) x^{3} + 13 x^{2} + 32 x + 20

(i v) 2 y^{3} + y^{2} - 2 y - 1

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