Question

$I.x^2-19x+84=0$

$II.y^2-25y+156=0$

• A. (a)
• B. (b)
• C. (c)
• D. (d)
• E. (e)

Answer 1

The correct option is D

(d)

x${}^2$ - 19 x + 84 = 0

=$>$ x${}^2$ - 12 x - 7 x + 84 = 0

=$>$ x(x - 12) - 7 (x - 12) = 0

=$>$ (x - 7) (x - 12) = 0

So, x = 7 or x = 12

y${}^2$ - 25 y + 156 = 0

=$>$ y${}^2$ - 12 y - 13 y + 156 = 0

=$>$ y(y - 12) - 13 (y - 12) = 0

=$>$ (y - 13) (y - 12) = 0

So, y = 12 or 13

Thus, we see that $x\le y$