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Question

I.x2+4x+4=0

II.y2−8y+16=0


A

(a)

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B

(b)

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C

(c)

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D

(d)

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E

(e)

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Solution

The correct option is B

(b)


x 2 + 4x + 4 = 0

(x + 2)2 = 0 =>x = - 2

y2 - 8y + 16 = 0

=>(y- 4)2 = 0

=>y = 4

Thus, we see that x<y


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