I- x2-4 x-4-0II- y 2-8 y -16-0A- cB- dC- bD- eE- a

The correct option is C (b) x ^2 + 4x + 4 = 0 (x + 2)^2 = 0 =gt;x = 2 y^2 8y + 16 = 0 =gt;(y 4)^2 = 0 =gt;y = 4 Thus, we see that x lt;y ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Chain Rule of Differentiation

I. x2+4 x+4=0...

Question

$I . x^{2} + 4 x + 4 = 0$

$I I . y^{2} - 8 y + 16 = 0$

(a)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(b)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(c)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(d)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(e)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

I . x^{2} + 4 x + 4 = 0

I I . y^{2} - 8 y + 16 = 0

I . x^{2} - 16 = 0

I I . y^{2} - 9 y + 20 = 0

x^{2} + 4 x + 4 = 0

y^{2} - 8 y + 16 = 0

x^{2} - 4 = 0

y^{2} + 6 y + 9 = 0

x^{2} + 9 x + 14 = 0

y^{2} + y - 2 = 0

Join BYJU'S Learning Program