Question

$I.X^2+5X+6=0$
$II.4Y^2+24Y+35=0$

• A. $X\ge Y$
• B. $X\le Y$
• C. $X<Y$
• D. $X>Y$
• E. Relationship between X and Y cannot be established

Answer 1

The correct option is E Relationship between X and Y cannot be established

Equation I
$X^2+5X+6=0$
$\Rightarrow X^2+3X+2X+6=0$
$\Rightarrow X(X+3)+2(X+3)=0$
$\Rightarrow (X+2)(X+3)=0$
$\therefore X=-2or-3$
Equation II
$4Y^2+24Y+35=0$
$\Rightarrow 4Y^2+14Y+10Y+35=0$
$\Rightarrow 2Y(2Y+7)+5(2Y+7)=0$
$\Rightarrow (2Y+5)(2Y+7)=0$
$\therefore Y=-\frac{5}{2}or-\frac{7}{2}$
Hence relationship between X and Y cannot be established.