Question

$I.(x{)}^2=961$
$II.y=\sqrt{961}$

• A. x > y
• B. x $\ge$ y
• C. x < y
• D. x $\le$ y
• E. x = y or the relationship cannot be established

Answer 1

The correct option is E x = y or the relationship cannot be established

Equation I
$x^2=961$
$\Rightarrow x=\pm \sqrt{961}\Rightarrow x=\pm 31$
Equation II
$y=\sqrt{961}$
$\Rightarrow y=\pm 31$
Hence, x = y