I- x2-9 x-14-0II- y 2- y -2-0A- If x - yB- If xy

The correct option is C If x ≤ yEquation I x^2+9x+14=0 ⇒ x^2+2x+7x+14=0 ⇒ x(x+2)+7(x+2)=0 ⇒ (x+2)(x+7)=0 ⇒ x= 2 or x= 7 Equation II y^2+y 2=0 ⇒ y^2+2y y 2=0 ⇒ ...

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Byju's Answer

Standard XII

Mathematics

Derivative of Standard Functions

I. x2+9 x+14=...

Question

I. $x^{2} + 9 x + 14 = 0$
II. $y^{2} + y - 2 = 0$

x < y

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x \leq y

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x = y

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x > y

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x \geq y

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Solution

The correct option is B If $x \leq y$
Equation I
$x^{2} + 9 x + 14 = 0$
$\Rightarrow x^{2} + 2 x + 7 x + 14 = 0$
$\Rightarrow x (x + 2) + 7 (x + 2) = 0$
$\Rightarrow (x + 2) (x + 7) = 0$
$\Rightarrow x = - 2$ or $x = - 7$

Equation II
$y^{2} + y - 2 = 0$
$\Rightarrow y^{2} + 2 y - y - 2 = 0$
$\Rightarrow y (y + 2) - 1 (y + 2) = 0$
$\Rightarrow (y - 1) (y + 2) = 0$
$\Rightarrow y = 1$ or $y = - 2$
Hence, $x \leq y$

Suggest Corrections

I. x2+9x+14=0 II. y2+y−2=0

The correct option is B If x≤yEquation I x2+9x+14=0 ⇒x2+2x+7x+14=0 ⇒x(x+2)+7(x+2)=0 ⇒(x+2)(x+7)=0 ⇒x=−2 or x=−7 Equation II y2+y−2=0 ⇒y2+2y−y−2=0 ⇒y(y+2)−1(y+2)=0 ⇒(y−1)(y+2)=0 ⇒y=1 or y=−2 Hence, x≤y

I. $x^{2} + 9 x + 14 = 0$
II. $y^{2} + y - 2 = 0$