I- x2-x-20-0II- y 2- y -30-0A- if xyE- if x - y

The correct option is E if x ≤ y I. x^2+ x 20 = 0 Or x^2+ 5x 4x 20 = 0 Or x (x + 5) 4 (x + 5) = 0 Or (x + 5) (x 4) = 0 Therefore x = 5 or 4 II. y^2 ...

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Quantitative Aptitude

Maxima/Minima of a Quadratic Equation

I. x2+x-20=0I...

Question

$I . x^{2} + x - 20 = 0$
$I I . y^{2} - y - 30 = 0$

if x > y

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if x ≥ y

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if x < y

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if x ≤ y

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if x = y or the relationship cannot be established

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Solution

The correct option is D
if x ≤ y

I. $x^{2}$ + x - 20 = 0
Or $x^{2}$ + 5x - 4x - 20 = 0
Or x (x + 5) - 4 (x + 5) = 0
Or (x + 5) (x - 4) = 0
Therefore x = -5 or 4
II. $y^{2}$ - y - 30 = 0
Or $y^{2}$ + 5y - 6y - 30 = 0
Or y (y + 5) - 6 (y + 5) = 0
Or (y + 5) (y - 6) = 0
Therefore y = -5 or 6
So $x \leq y$ is the answer.

Suggest Corrections

I.x2+x−20=0 II.y2−y−30=0

The correct option is D if x ≤ y I. x2+ x - 20 = 0 Or x2+ 5x - 4x - 20 = 0 Or x (x + 5) - 4 (x + 5) = 0 Or (x + 5) (x - 4) = 0 Therefore x = -5 or 4 II. y2- y - 30 = 0 Or y2+ 5y - 6y - 30 = 0 Or y (y + 5) - 6 (y + 5) = 0 Or (y + 5) (y - 6) = 0 Therefore y = -5 or 6 So x≤y is the answer.

$I . x^{2} + x - 20 = 0$
$I I . y^{2} - y - 30 = 0$