Question

$I.x^3\times 13=x^2\times 247$
$II.y^{1/3}\times 14=294÷y^{2/3}$

• A. x > y
• B. x $\ge$ y
• C. x < y
• D. x $\le$ y
• E. x = y or the relationship cannot be established

Answer 1

The correct option is C x < y

Equation I
$x^3\times 13=x^2\times 247$
$\Rightarrow \frac{x^3}{x^2}=\frac{247}{13}$
$\therefore x=19$
Equation II
$y^{1/3}\times 14=294÷y^{2/3}$
$\Rightarrow (y{)}^{1/3}\times (y{)}^{2/3}=\frac{194}{14}$
$\Rightarrow (y{)}^{1/3÷2/3}=21$
$\therefore y=21$
Hence, y > x