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Question

(i) x=asinθbcosθ
y=acosθ+bsinθ

A
x2+y2=a2+b2
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B
x2+y2=a2
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C
x2y2=a2+b2
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D
x2y2=a2+b2
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Solution

The correct option is D x2+y2=a2+b2
x2+y2=(asinθbcosθ)2+(acosθ+bsinθ)2
=a2sin2θ+b2cos2θ2absinθcosθ+a2cos2θ+b2sin2θ+2absinθcosθ
x2+y2=a2+b2.

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