Ideal gas equation in terms of KE per unit volume, $E$ , is

P V = \frac{3}{2} R T

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P V = \frac{2}{3} E

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P V = \frac{2}{3} R T

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P V = \frac{3}{2} E

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Solution

The correct option is B $P V = \frac{2}{3} E$
As we know,
$K E = \frac{3}{2} R T$
Also by ideal gas equation,
$P V = R T = \frac{2}{3} (K E)$

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