Ideal gas is taken through the process shown in figure
A
in process AB, work done by system is positive
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B
In process AB, heat is rejected out of the system
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C
In process AB, internal energy increases
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D
In process AB internal energy decreases and in process BC internal energy increases.
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Solution
The correct option is B In process AB, heat is rejected out of the system Process A to B is isochoric process has work done zero and by first law of thermodynamics.
Heat=ΔU+work
if work is zero Heat=ΔU=mCΔT
Since the process is moving form A to B the heat is rejected out of system.