Identical cylinders contain helium at 2.5 atm and agron at 1 atm respectively. If the are filled in one of the cylinder,the pressure would be.

3.6 atm

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1.75 atm

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1.5 atm

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1.0 atm

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Solution

The correct option is A 1.75 atm
Given that,

Pressure $p_{1} = 2.5 a t m$

Pressure $P_{2} = 1 a t m$

Volume $V_{1} = V_{2} = V$

Both the cylinders are similar, volume of both the gases is equal

Let the volume of gases be V

The amount of pressure P in one of the cylinder will be equal to the total pressure at equilibrium

Now,

$P = \frac{P_{1} V_{1} + P_{2} V_{2}}{V_{1} + V_{2}}$

$P = \frac{2.5 \times V + 1 \times V}{2 V}$

$P = 1.75 a t m$

Hence, the pressure is $1.75 a t m$

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