Question

Identify A and B in the chemical reaction.

\( HCl \longrightarrow \) [A] (major) \( \underset{\text { Dry acetone }}{\stackrel{ NaI }{\longrightarrow}} \underset{\text { (major) }}{[ B ]} \)
(JEE MAIN 2021)

• A.
• B.
• C.
• D.

Answer 1

The correct option is B \( A = \) \( B= \)

In first step, alkene attacks the $H^{+}$ to form stable carbocation (here $N{O}_2$ is electron withdrawing group so carbocation formed at carbon far from it is more stable) followed by addition of $C{l}^{-}$. The aryl chloride formed with NaI undergoes Finkelstein reaction to form alkyl iodide. Here, alkyl iodide product is stable because $NaCl$ is insoluble in acetone so $I^{-}$ is the active nucleophile here.
\( \stackrel{ Cl ^{-}}{\longrightarrow} \) \( NaI / \) Acetone
Hence, correct option should be (a).