Identify A and B in the given reaction.
$P y r u v i c a c i d + C o A + {N A D}^{+} M g^{2 +} - -------------- \to P y r u v a t e d e h y d r o g e n a s e A + B + N A D H + H^{+}$

A- PEP ; B-

C O_{2}

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A-Acetyl CoA ; B-

C O_{2}

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A-

C O_{2}

; B-

H_{2} O

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A- Acetyl CoA ; B-

H_{2} O

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Solution

The correct option is D A-Acetyl CoA ; B- $C O_{2}$

During aerobic respiration, pyruvic acid which is formed during glycolysis enters mitochondrial matrix. It undergoes oxidative decarboxylation to produce ${C O}_{2}$ and NADH. The product combines with sulfur-containing co-enzyme A to form acetyl CoA. This reaction is catalyzed by an enzyme complex pyruvate dehydrogenase. This step is called link reaction or gateway step as it links glycolysis with Krebs' cycle.
$P y r u v i c a c i d + C O A + {N A D}^{+} M g^{2 +} - -------------- \to P y r u v a t e d e h y d r o g e n a s e A c e t y l C o A + {C O}_{2} + N A D H + H^{+}$
So the correct answer is 'A-Acetyl CoA ; B- $C O_{2}$ '.

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