Identify A and B in the given schematic diagram of a galvanic cell.

A -

F e

and B-

C u S O_{4}

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A -

Z n

and B-

Z n S O_{4}

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A -

Z n

and B-

F e S O_{4}

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A -

F e

and B-

Z n S O_{4}

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Solution

The correct option is A A - $F e$ and B- $C u S O_{4}$
The device used for the conversion of chemical energy into electrical energy is called a galvanic cell. In the arrangement of a galvanic cell, the electrode is dipped in its own salt solution so it can lose electrons in its aqueous solution and form its positive ions. Therefore, $F e$ will be dipped in $F e S O_{4}$ and $C u$ will be dipped in $C u S O_{4}$ solution

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Similar questions

Q. The emf of a galvanic cell constituted with the electrodes

{Z n}^{2 +} | Z n (- 0.76 V)

and

{F e}^{2 +} | F e (- 0.41 V)

is :

Q. Construct the cells in which the following reactions are taking place. Which of the electrodes shall act as anode (negative electrode) and which one as cathode (positive electrode)?
(a)

Z n + C u S O_{4} = Z n S O_{4} + C u

(b)

C u + 2 A g N O_{3} = C u (N O_{3})_{2} + 2 A g

(c)

Z n + H_{2} S O_{4} = Z n S O_{4} + H_{2}

(d)

F e + S n C l_{2} = F e C l_{2} + S n

Q. Which of the following reactions will take place?
A. Mg + ZnSO₄ → MgSO₄ + Zn
B. Zn + CuCl₂ → ZnCl₂ + Cu
C. Cu + FeSO₄ → CuSO₄ + Fe
D. Fe + MgCl₂ → FeCl₂ + Mg

(a) C and D
(b) A and B
(c) A, B and C
(d) all the above

Given the standard reduction potentials:

Zn²⁺/Zn = - 0.74 V, Cl₂/Cl^- = 1.36 V, H⁺/1/2H₂ = 0 V and Fe³⁺/Fe²⁺ = 0.77 V.
The order of increasing strength as reducing agent is

Q. For an electrochemical reaction occurring in a galvanic cell.

2 F e_{(a q)}^{+ 3} + Z n_{(s)} \to Z n_{(a q)}^{+ 2} + 2 F e_{(a q)}^{+ 2}

if concentration of

F e^{+ 2}

is increased.

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