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Question
Identify A,B,C,D,E,R and R′ in the following:
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Solution
Identification of A and B
Bromocyclohexane will react with Mg to give organo-metallic compound/Grignard reagent i.e. Cyclohexyl magnesium bromide (A).
Cyclohexyl magnesium bromide reacts with water to give cyclohexane (B) and Mg(OH)Br.
Identification of C and R
R−Br reacts with metal (Mg) to form the Grignard reagent (C) and further reaction with D20 gives alkane.
C is CH3CH(MgBr)CH3
So, R should be: 
.
Identification of D,E and R′
As we know, alkyl halides in the presence of Na/dry ether gives symmetrical alkane containing double the number of carbon atoms in reactant (Wurtz reaction).
In the reaction 2,2,3,3−tetramethyl butane is formed as product after the alkyl halide reacts in the presence of sodium in dry ether.
Therefore, R′ is(CH3)3C.
Now, alky halide reacts with Magnesium to give Grignard reagent (D) and fruther with H2O to give alkane (E).
So, D is (CH3)3C−MgBr and E is (CH3)3 C−H.
Identification of A and B
Bromocyclohexane will react with Mg to give organo-metallic compound/Grignard reagent i.e. Cyclohexyl magnesium bromide (A).
Cyclohexyl magnesium bromide reacts with water to give cyclohexane (B) and Mg(OH)Br.
R−Br reacts with metal (Mg) to form the Grignard reagent (C) and further reaction with D20 gives alkane.
C is CH3CH(MgBr)CH3
So, R should be:
.Identification of D,E and R′
As we know, alkyl halides in the presence of Na/dry ether gives symmetrical alkane containing double the number of carbon atoms in reactant (Wurtz reaction).
In the reaction 2,2,3,3−tetramethyl butane is formed as product after the alkyl halide reacts in the presence of sodium in dry ether.
Therefore, R′ is(CH3)3C.
Now, alky halide reacts with Magnesium to give Grignard reagent (D) and fruther with H2O to give alkane (E).
So, D is (CH3)3C−MgBr and E is (CH3)3 C−H.
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