The correct option is B BiCl_3 The solid A is bismuth trichloride #160; BiCl_3 .With water, it forms white turbidity of bismuth oxychloride BiCl ...

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Variable Oxidation States

Identify A

Question

Identify A

B i O C l

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B i_{2} S_{3}

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B i C l_{3}

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B a S O_{4}

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Solution

The correct option is B $B i C l_{3}$
The solid A is bismuth trichloride $B i C l_{3}$ .With water, it forms white turbidity of bismuth oxychloride $B i C l_{3} + H_{2} O \to B i O C l ↓ + 2 H C l$ . In presence of HCl, bismuth trichloride reacts with hydrogen sulphide to form black precipitate of bismuth sulphide. $2 B i C l_{3} + 3 H_{2} S B - - \to H C l i_{2} S_{3} + 6 H C l$ . Same reaction is also given with bismuth oxychloride. Bismuth trichloride reacts with sulphuric acid to form bismuth sulphate. $2 B i C l_{3} + 3 H_{2} S O_{4} \to B i_{2} (S O_{4})_{3} + 6 H C l$ . HCl gas is water soluble and nd gives white precipitate E with a solution of mercurous salts but not with mercuric salts.
$H g_{2} (N O_{3})_{2} + 2 H C l \to H g_{2} C l_{2} + 2 H N O_{3}$

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