Question

Identify $B,X$ and $R$ respectively in the following sequence of reactions:
$C_2{H}_{5}MgBr\underset{}{\overset{C{H}_{3}CN}{\to }}A\underset{}{\overset{H_3{O}^{+}}{\to }}B$,
${CH}_{3}CO{CH}_3\underset{I_2}{\overset{NaOH}{\to }}X\underset{}{\overset{Ag}{\to }}Y$
$C_6{H}_5{NH}_2\underset{HCl}{\overset{Na{NO}_2}{\to }}P\underset{}{\overset{CuCN}{\to }}Q\underset{}{\overset{+4H}{\to }}R$

• A. $C_2{H}_{5}COOH$, $CH{I}_3$, $C_6{H}_5{CH}_2{NH}_2$
• B. $C_2{H}_{5}COOH$, ${CH}_{3}I$, $C_6{H}_{5}COOH$
• C. $C_2{H}_5{CH}_2{NH}_2$, ${CH}_{3}I$, $C_6{H}_{5}COOH$
• D. $C_2{H}_{5}COOH$, $C_2{H}_{5}I$, $C_6{H}_{5}CO{NH}_2$

Answer 1

The correct option is A $C_2{H}_{5}COOH$, $CH{I}_3$, $C_6{H}_5{CH}_2{NH}_2$

The products $B,X$ and $R$ are $C_2{H}_{5}COOH$, $CH{I}_3$, $C_6{H}_5{CH}_2{NH}_2$ respectively.
Ethyl magnesium bromide reacts with acetonitrile followed by acid hydrolysis gives $but-2-one$ (compound B).
Acetone on haloform reaction with $NaOH$ in iodine gives a mixture of sodium acetate and iodoform (compound X).
Aniline on diazotization followed by sandmeyer reaction with $CuCN$ gives benzonitrile which on reduction forms benzylamine (compound R).