Question

Identify Bronsted-Lowry acids in the reaction given below?
$\underset{A}{{\left[Al{\left(H_{2}O\right)}_6\right]}^{3+}}+\underset{B}{H{CO}_3^{-}}\rightleftharpoons \underset{C}{{\left[Al{\left(H_{2}O\right)}_5\right(OH\left)\right]}^{2+}}+\underset{D}{H_2{CO}_3}$
The correct answer is:

• A. A, C
• B. A, D
• C. B, D
• D. B, C

Answer 1

The correct option is A A, C

Bronsted Lowry acid is that reactant in a reaction that loses proton and it is accepted by bronsted base. In the above reaction reactant A ($\left[Al\right(H_{2}O{)}_6{]}^{+3}$ loses one proton from one $H_{2}O$ and formed product C$\left[Al\right(H_{2}O{)}_5{OH]}^{+2}$