Question

Identify complexes with different geometries depending upon the type of hybridization.
$\left[Co/\right(N{H}_3{)}_6{]}^{2+}$.

Answer 1

$\left[Co\right(N{H}_3{)}_6{]}^{2+}⟶C{o}^{2+}$

$Co⟶3d^{7}4s^2$

$C{a}^{+2}⟶3d^{7}4s^0$

as $N{H}_3$ is a weak field ligand, thus it will not make the electron paired of $Co$ and form outer d complex.

(Refer to Image)

Thus hybridization is $s{p}^3{d}^2$ and geometry is octahedral .