Question

Identify correct order of average molecular dipole moment.

• A. $P{Cl}_3{F}_2>N_2{O}_{4\left(g\right)}>N_2{O}_{4\left(s\right)}$
• B. $P{Cl}_3{F}_2<N_2{O}_{4\left(g\right)}<N_2{O}_{4\left(s\right)}$
• C. $P{Cl}_3{F}_2<N_2{O}_{4\left(g\right)}=N_2{O}_{4\left(s\right)}$
• D. All are incorrect.

Answer 1

Answer: (A)

$P{Cl}_3{F}_2>N_2{O}_{4\left(g\right)}>N_2{O}_{4\left(s\right)}$

Correct Option $-D$

Reason:- $PC{l}_3{F}_2$ has a symmetrical & thus has a zero dipole moment. Increasing dipole moments N from $N_2{O}_4$${}_{\left(s\right)}$ to $N_2{O}_4$${}_{\left(g\right)}$is due to the fact that dipole moment=charge*distance.