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Valency and Oxidation State

Identify E an...

Question

Identify (E) and (F) in the following:

FeSO $_{4}$ (A) $Δ \to$ (B) + (C) + (D)

(C) and (D) are gases, (B) is red-brown solid, (C) can be oxidised to (D). (C) also turns Cr $_{2}$ O $_{7}^{2 -}$ /H $^{+}$ solution green. (B) dissolves in HCl forming deep yellow solution (E). (E) gives blue colour (F) with K $_{4} [F e (C N)_{6}]$ . (D) dissolves in H $_{2}$ O forming a well knows mineral acid called "king of acids".

A

(E) : FeCl

_{2}

(F) : KFe

^{I I}

[Fe

^{I I I}

(CN)

_{6}

]

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B

(E) : FeCl

_{2}

(F) : KFe

^{I I I}

[Fe

^{I I}

(CN)

_{6}

]

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C

(E) : FeCl

_{3}

(F) : KFe

^{I I}

[Fe

^{I I I}

(CN)

_{6}

]

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D

(E) : FeCl

_{3}

(F) : KFe

^{I I I}

[Fe

^{I I}

(CN)

_{6}

]

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Solution

The correct option is D (E) : FeCl $_{3}$ (F) : KFe $^{I I I}$ [Fe $^{I I}$ (CN) $_{6}$ ]
(A): $F e S O_{4}$ (B): $F e_{2} O_{3}$ (C): $S O_{2}$ (D): $S O_{3}$ (E): $F e C l_{3}$ (F): $K F e^{I I I} [F e^{I I} (C N)_{6}]$ Prussian blue

Reaction:
FeSO $_{4}$ (A) $Δ \to$ Fe $_{2} O_{3}$ (B) + SO $_{2}$ (C) + SO $_{3}$ (D)

$S O_{2}$ and $S O_{3}$ are gases
$F e_{2} O_{3}$ is red-brown solid
$S O_{2}$ can be oxidised to $S O_{3}$
$S O_{2}$ also turns $C r_{2} O_{7}^{2 -} / H^{+}$ solution green.
$F e_{2} O_{3}$ dissolves in $H C l$ forming deep yellow solution $F e C l_{3}$ .
$F e C l_{3}$ gives blue colour complex $K F e^{I I I} [F e^{I I} (C N)_{6}]$ with K $_{4} [F e (C N)_{6}]$
$S O_{3}$ dissolves in $H_{2} O$ forming a well knows mineral acid called "king of acids".

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Similar questions

d i l . H_{2} S O_{4} ⟶

(B) + (C) + (D) (gas)
(D) +

C H_{3} C O O)_{2} P b △ ⟶

(B) + (C) (D) \to

E (black ppt) separated from (C) by filtration
(E) +

H N O_{3} d i l . △ \to

(F) blue coloured solution
(F) +

K_{4} [F e (C N)_{6}] ⟶

(C) chocolate coloured ppt
(C) +

K_{3} [F e (C N)_{6}] ⟶

A to H are identified as: (A) :

C u F e S_{2}

C u S O_{4}

F e S O_{4}

H_{2} S

C u S

C u (N O_{3})_{2}

C u_{2} [F e (C N)_{6}]

K F e^{I I} [F e^{I I I} (C N)_{6}]

, Turnbull's blue

Show the above reaction.

Q. Identify the correct order of flocculation value for

F e (O H)_{3}

Q. Turnbull's blue and Prussian's blue respectively are

{K F e}^{I I} {[{F e}^{I I I} (C N)}_{6}], {K F e}^{I I I} {[{F e}^{I I} (C N)}_{6}]

If the given statement is true enter 1 else enter 0.

In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:
(a) $N a_{4} [F e (C N)_{6}]$ (b) $F e_{4} [F e (C N)_{6}]^{3}$ (c) $F e_{2} [F e (C N)_{6}]$ (d) $F e_{3} [F e (C N)_{6}]_{4}$

Q. In the following redox reactions, what is the value of

f

?

I

a M n O_{4}^{-} + b {F e}^{2 +} + c H^{+} ⟶ d {M n}^{2 +} + e {F e}^{3 +} + f H_{2} O

I I

a {C r}_{2} O_{7}^{2 -} + b {F e}^{2 +} + c H^{+} ⟶ d {C r}^{3 +} + e {F e}^{3 +} + f H_{2} O

I I I

a M n O_{4}^{-} + b H_{2} O_{2} + c H^{+} ⟶ d {M n}^{2 +} + e O_{2} + f H_{2} O

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