Identify F:

H F

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N H_{3}

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H N_{3}

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None ofthese

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Solution

The correct option is C $H N_{3}$
A colorless water soluble crystalline solid (A) on heating gives $O_{2}$ and gives a water soluble crystalline solid (B).
$2 K N O_{3} (s) \to 2 K N O_{2} (s) + O 2 (g)$
So, A iS $K N O_{3}$ (crystalline solid) and B is $K N O_{2}$ (water soluble crystalline solid).Both A and B impart violet coloration to the Bunsen flame
When B is heated with $N H_{4} C l$ , inactive gas (C) is obtained but when A is heated with $N H_{4} C l$ , a gas (D)which supports combustion is formed.
$N H_{4} C l + K N O_{2} \to N_{2} + K C l + 2 H_{2} O$
So the gas C is $N_{2}$ .
But when A is heated with $N H_{4} C l$ , a gas (D) which supports combustion is formed.
$N H_{4} C l + K N O_{3} \to N H_{4} N O_{3} + K C l$
A gas (D) which supports combustion is $N H_{4} N O_{3}$
When gas(D) is heated with soda amide, solid substance E is obtained
$N H_{4} N O_{3} + N a N H_{2} \to N a N_{2} + 2 N H_{3} + N a N O_{3}$
solid substance E is $N a N_{2}$ .
The solid E, when heated with diI. $H_{2} S O_{4}$ , forms a monobasic acid F; F and its salts are explosive.
$N a N 3 + H_{2} S O_{4} \to H N_{3} + N a H S O_{4}$
A monobasic acid F is $H_{3} N$
So F is $H_{3} N$
Hence option C is correct.

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Similar questions

The order of boiling point of $N H_{3}, H_{2} O, H F a n d P H_{3}$ is

C H_{4}, N H_{3}, H_{2} O, H F

S b F_{6}, A s F_{5}

B F_{3}

F^{-} f r o m H F

A s F_{5} + H F ⇌ H^{+} + [A s F_{6}]^{-}

B F_{3} + H F ⇌ H^{+} + [B F_{4}]^{-}

N F_{3}, N O_{3}^{-}, B F_{3}, H_{3} O^{+}, H N_{3}

N a C l + H_{2} O

C O_{2} + N H_{3}

\to

N H_{4} C l

X

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